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5404125433 = 71021756139
BaseRepresentation
bin1010000100001110…
…00110100011111001
3111221121211000102211
411002013012203321
542031424003213
62252125055121
7250630210510
oct50207064371
914847730384
105404125433
112323540473
1210699b74a1
136817b5b75
14393a1b677
1521968253d
hex1421c68f9

5404125433 has 8 divisors (see below), whose sum is σ = 6182200640. Its totient is φ = 4627564560.

The previous prime is 5404125409. The next prime is 5404125451. The reversal of 5404125433 is 3345214045.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5404125433 - 213 = 5404117241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5404125395 and 5404125404.

It is not an unprimeable number, because it can be changed into a prime (5404125533) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 370923 + ... + 385216.

It is an arithmetic number, because the mean of its divisors is an integer number (772775080).

Almost surely, 25404125433 is an apocalyptic number.

It is an amenable number.

5404125433 is a deficient number, since it is larger than the sum of its proper divisors (778075207).

5404125433 is a wasteful number, since it uses less digits than its factorization.

5404125433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 757167.

The product of its (nonzero) digits is 28800, while the sum is 31.

The square root of 5404125433 is about 73512.7569405474. The cubic root of 5404125433 is about 1754.8573010275.

Adding to 5404125433 its reverse (3345214045), we get a palindrome (8749339478).

The spelling of 5404125433 in words is "five billion, four hundred four million, one hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 7 1021 7147 756139 5292973 772017919 5404125433