Base | Representation |
---|---|
bin | 111101011100001110001001… |
… | …0101111101100000110000001 |
3 | 2121212112120222211000112120121 |
4 | 1322320130102233230012001 |
5 | 1031314033311121023431 |
6 | 5153230511112540241 |
7 | 221556345354110020 |
oct | 17270342257540601 |
9 | 2555476884015517 |
10 | 540440344314241 |
11 | 1472235101296a8 |
12 | 50744b619b1681 |
13 | 1a2733c8a94277 |
14 | 9765648cd28b7 |
15 | 4273160d5e611 |
hex | 1eb8712bec181 |
540440344314241 has 16 divisors (see below), whose sum is σ = 653981842141056. Its totient is φ = 435983080939776.
The previous prime is 540440344314197. The next prime is 540440344314271. The reversal of 540440344314241 is 142413443044045.
It is a cyclic number.
It is not a de Polignac number, because 540440344314241 - 229 = 540439807443329 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (540440344314271) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9268815 + ... + 34158331.
It is an arithmetic number, because the mean of its divisors is an integer number (40873865133816).
Almost surely, 2540440344314241 is an apocalyptic number.
It is an amenable number.
540440344314241 is a deficient number, since it is larger than the sum of its proper divisors (113541497826815).
540440344314241 is a wasteful number, since it uses less digits than its factorization.
540440344314241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25072008.
The product of its (nonzero) digits is 1474560, while the sum is 43.
Adding to 540440344314241 its reverse (142413443044045), we get a palindrome (682853787358286).
The spelling of 540440344314241 in words is "five hundred forty trillion, four hundred forty billion, three hundred forty-four million, three hundred fourteen thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •