Base | Representation |
---|---|
bin | 1111101110110100101… |
… | …11111101011101010011 |
3 | 1220200012210021001220211 |
4 | 13313122113331131103 |
5 | 32324003331014011 |
6 | 1052152420544551 |
7 | 54023644341043 |
oct | 7673227753523 |
9 | 1820183231824 |
10 | 540534626131 |
11 | 19926a783015 |
12 | 88913b52157 |
13 | 3bc83bb9c56 |
14 | 1c23a7db723 |
15 | e0d9522b21 |
hex | 7dda5fd753 |
540534626131 has 16 divisors (see below), whose sum is σ = 589564519200. Its totient is φ = 493620438528.
The previous prime is 540534626117. The next prime is 540534626209. The reversal of 540534626131 is 131626435045.
It is not a de Polignac number, because 540534626131 - 29 = 540534625619 is a prime.
It is a super-4 number, since 4×5405346261314 (a number of 48 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (540534626101) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 462406 + ... + 1137931.
It is an arithmetic number, because the mean of its divisors is an integer number (36847782450).
Almost surely, 2540534626131 is an apocalyptic number.
540534626131 is a deficient number, since it is larger than the sum of its proper divisors (49029893069).
540534626131 is a wasteful number, since it uses less digits than its factorization.
540534626131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1600998.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 540534626131 in words is "five hundred forty billion, five hundred thirty-four million, six hundred twenty-six thousand, one hundred thirty-one".
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