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54071433 = 3213462149
BaseRepresentation
bin1100111001000…
…1000010001001
310202202010001200
43032101002021
5102320241213
65210534413
71224412443
oct316210211
9122663050
1054071433
1128581739
1216137409
13b282640
147277493
154b31273
hex3391089

54071433 has 12 divisors (see below), whose sum is σ = 84111300. Its totient is φ = 33274656.

The previous prime is 54071431. The next prime is 54071443. The reversal of 54071433 is 33417045.

It can be written as a sum of positive squares in 2 ways, for example, as 23068809 + 31002624 = 4803^2 + 5568^2 .

It is not a de Polignac number, because 54071433 - 21 = 54071431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54071397 and 54071406.

It is not an unprimeable number, because it can be changed into a prime (54071431) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 230958 + ... + 231191.

It is an arithmetic number, because the mean of its divisors is an integer number (7009275).

Almost surely, 254071433 is an apocalyptic number.

It is an amenable number.

54071433 is a deficient number, since it is larger than the sum of its proper divisors (30039867).

54071433 is a wasteful number, since it uses less digits than its factorization.

54071433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 462168 (or 462165 counting only the distinct ones).

The product of its (nonzero) digits is 5040, while the sum is 27.

The square root of 54071433 is about 7353.3280220591. The cubic root of 54071433 is about 378.1429080879.

Adding to 54071433 its reverse (33417045), we get a palindrome (87488478).

The spelling of 54071433 in words is "fifty-four million, seventy-one thousand, four hundred thirty-three".

Divisors: 1 3 9 13 39 117 462149 1386447 4159341 6007937 18023811 54071433