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540811403 = 1149164673
BaseRepresentation
bin100000001111000…
…010000010001011
31101200122001202222
4200033002002023
52101421431103
6125355244255
716254551426
oct4017020213
91350561688
10540811403
11258301680
1213114968b
1388074062
1451b7a9bd
153272a638
hex203c208b

540811403 has 4 divisors (see below), whose sum is σ = 589976088. Its totient is φ = 491646720.

The previous prime is 540811393. The next prime is 540811433. The reversal of 540811403 is 304118045.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 540811403 - 28 = 540811147 is a prime.

It is a super-2 number, since 2×5408114032 = 584953947229656818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (540811433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24582326 + ... + 24582347.

It is an arithmetic number, because the mean of its divisors is an integer number (147494022).

Almost surely, 2540811403 is an apocalyptic number.

540811403 is a deficient number, since it is larger than the sum of its proper divisors (49164685).

540811403 is a wasteful number, since it uses less digits than its factorization.

540811403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49164684.

The product of its (nonzero) digits is 1920, while the sum is 26.

The square root of 540811403 is about 23255.3521366588. The cubic root of 540811403 is about 814.7329487501.

Adding to 540811403 its reverse (304118045), we get a palindrome (844929448).

The spelling of 540811403 in words is "five hundred forty million, eight hundred eleven thousand, four hundred three".

Divisors: 1 11 49164673 540811403