Base | Representation |
---|---|
bin | 11000100110100001010111… |
… | …10000100111101100100011 |
3 | 21002112220220221010011000011 |
4 | 30103100223300213230203 |
5 | 24042334042402214321 |
6 | 311021132350505351 |
7 | 14252414646334354 |
oct | 1423205360475443 |
9 | 232486827104004 |
10 | 54100142226211 |
11 | 16268817998484 |
12 | 6098b78205257 |
13 | 2425810637863 |
14 | d5066482bd2b |
15 | 63c40759aae1 |
hex | 31342bc27b23 |
54100142226211 has 4 divisors (see below), whose sum is σ = 54106802352792. Its totient is φ = 54093482099632.
The previous prime is 54100142226197. The next prime is 54100142226287. The reversal of 54100142226211 is 11262224100145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54100142226211 - 215 = 54100142193443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54100142220211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3330051106 + ... + 3330067351.
It is an arithmetic number, because the mean of its divisors is an integer number (13526700588198).
Almost surely, 254100142226211 is an apocalyptic number.
54100142226211 is a deficient number, since it is larger than the sum of its proper divisors (6660126581).
54100142226211 is an equidigital number, since it uses as much as digits as its factorization.
54100142226211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6660126580.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 54100142226211 its reverse (11262224100145), we get a palindrome (65362366326356).
The spelling of 54100142226211 in words is "fifty-four trillion, one hundred billion, one hundred forty-two million, two hundred twenty-six thousand, two hundred eleven".
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