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5410231202001 = 31803410400667
BaseRepresentation
bin100111010111010101011…
…1010001011000011010001
3201011012202022111102001110
41032232222322023003101
51202120123141431001
615301231554523533
71065606400305333
oct116565272130321
921135668442043
105410231202001
1117a65145183aa
127346575965a9
1330324b280192
14149bdc693453
1595aec4473d6
hex4ebaae8b0d1

5410231202001 has 4 divisors (see below), whose sum is σ = 7213641602672. Its totient is φ = 3606820801332.

The previous prime is 5410231201993. The next prime is 5410231202017. The reversal of 5410231202001 is 1002021320145.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5410231202001 - 23 = 5410231201993 is a prime.

It is a super-3 number, since 3×54102312020013 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5410231202021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 901705200331 + ... + 901705200336.

It is an arithmetic number, because the mean of its divisors is an integer number (1803410400668).

Almost surely, 25410231202001 is an apocalyptic number.

It is an amenable number.

5410231202001 is a deficient number, since it is larger than the sum of its proper divisors (1803410400671).

5410231202001 is a wasteful number, since it uses less digits than its factorization.

5410231202001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1803410400670.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 5410231202001 its reverse (1002021320145), we get a palindrome (6412252522146).

The spelling of 5410231202001 in words is "five trillion, four hundred ten billion, two hundred thirty-one million, two hundred two thousand, one".

Divisors: 1 3 1803410400667 5410231202001