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5410441133203 = 13844939078947
BaseRepresentation
bin100111010111011011101…
…1010111111110010010011
3201011020021221112000112011
41032232313122333302103
51202121040412230303
615301304454243351
71065614526554551
oct116566732776223
921136257460464
105410441133203
1117a6611a73867
127346b5956557
13303282903922
14149c1c4dcbd1
1595b10ab416d
hex4ebb76bfc93

5410441133203 has 4 divisors (see below), whose sum is σ = 5410480350600. Its totient is φ = 5410401915808.

The previous prime is 5410441133129. The next prime is 5410441133213. The reversal of 5410441133203 is 3023311440145.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5410441133203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5410441133213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19401025 + ... + 19677922.

It is an arithmetic number, because the mean of its divisors is an integer number (1352620087650).

Almost surely, 25410441133203 is an apocalyptic number.

5410441133203 is a deficient number, since it is larger than the sum of its proper divisors (39217397).

5410441133203 is a wasteful number, since it uses less digits than its factorization.

5410441133203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39217396.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 5410441133203 its reverse (3023311440145), we get a palindrome (8433752573348).

The spelling of 5410441133203 in words is "five trillion, four hundred ten billion, four hundred forty-one million, one hundred thirty-three thousand, two hundred three".

Divisors: 1 138449 39078947 5410441133203