Base | Representation |
---|---|
bin | 11000100110111000011011… |
… | …01111001010101000000011 |
3 | 21002121002212210112111012101 |
4 | 30103130031233022220003 |
5 | 24043034421444233103 |
6 | 311030541115011231 |
7 | 14253333530000524 |
oct | 1423341557125003 |
9 | 232532783474171 |
10 | 54112523430403 |
11 | 16272aa0847439 |
12 | 609b452739b17 |
13 | 2426a3475c699 |
14 | d510bad1a84b |
15 | 63c8ce51aa1d |
hex | 31370dbcaa03 |
54112523430403 has 8 divisors (see below), whose sum is σ = 55978563707280. Its totient is φ = 52246489233120.
The previous prime is 54112523430341. The next prime is 54112523430409. The reversal of 54112523430403 is 30403432521145.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54112523430403 - 237 = 53975084476931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54112523430409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23657688 + ... + 25843978.
It is an arithmetic number, because the mean of its divisors is an integer number (6997320463410).
Almost surely, 254112523430403 is an apocalyptic number.
54112523430403 is a deficient number, since it is larger than the sum of its proper divisors (1866040276877).
54112523430403 is a wasteful number, since it uses less digits than its factorization.
54112523430403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3039797.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 54112523430403 its reverse (30403432521145), we get a palindrome (84515955951548).
The spelling of 54112523430403 in words is "fifty-four trillion, one hundred twelve billion, five hundred twenty-three million, four hundred thirty thousand, four hundred three".
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