Base | Representation |
---|---|
bin | 11000100110111001111111… |
… | …01010010010011100101011 |
3 | 21002121012001011121001212101 |
4 | 30103130333222102130223 |
5 | 24043043130404400043 |
6 | 311031200155154231 |
7 | 14253363350222101 |
oct | 1423347752223453 |
9 | 232535034531771 |
10 | 54113361012523 |
11 | 1627339061726a |
12 | 609b647145977 |
13 | 2426b391406c7 |
14 | d5115a269c71 |
15 | 63c92cd1824d |
hex | 31373fa9272b |
54113361012523 has 4 divisors (see below), whose sum is σ = 54113375742448. Its totient is φ = 54113346282600.
The previous prime is 54113361012511. The next prime is 54113361012553. The reversal of 54113361012523 is 32521016331145.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 54113361012523 - 213 = 54113361004331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54113361012553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3143098 + ... + 10867648.
It is an arithmetic number, because the mean of its divisors is an integer number (13528343935612).
Almost surely, 254113361012523 is an apocalyptic number.
54113361012523 is a deficient number, since it is larger than the sum of its proper divisors (14729925).
54113361012523 is an equidigital number, since it uses as much as digits as its factorization.
54113361012523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14729924.
The product of its (nonzero) digits is 64800, while the sum is 37.
Adding to 54113361012523 its reverse (32521016331145), we get a palindrome (86634377343668).
The spelling of 54113361012523 in words is "fifty-four trillion, one hundred thirteen billion, three hundred sixty-one million, twelve thousand, five hundred twenty-three".
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