54113510620993 has 4 divisors (see below), whose sum is σ = 54113685166980. Its totient is φ = 54113336075008.

The previous prime is 54113510620931. The next prime is 54113510621099. The reversal of 54113510620993 is 39902601531145.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 45029025274689 + 9084485346304 = 6710367^2 + 3014048^2 .

It is a cyclic number.

It is not a de Polignac number, because 54113510620993 - 2¹³ = 54113510612801 is a prime.

It is a super-3 number, since 3×54113510620993³ (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54113510620193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86807128 + ... + 87428281.

It is an arithmetic number, because the mean of its divisors is an integer number (13528421291745).

Almost surely, 2^{54113510620993} is an apocalyptic number.

It is an amenable number.

54113510620993 is a deficient number, since it is larger than the sum of its proper divisors (174545987).

54113510620993 is a wasteful number, since it uses less digits than its factorization.

54113510620993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 174545986.

The product of its (nonzero) digits is 874800, while the sum is 49.

The spelling of 54113510620993 in words is "fifty-four trillion, one hundred thirteen billion, five hundred ten million, six hundred twenty thousand, nine hundred ninety-three".