Base | Representation |
---|---|
bin | 11000100110111111011111… |
… | …00000110011011010001011 |
3 | 21002121110122210010000112111 |
4 | 30103133233200303122023 |
5 | 24043120201144103412 |
6 | 311032405030323151 |
7 | 14253526433333215 |
oct | 1423375740633213 |
9 | 232543583100474 |
10 | 54116311316107 |
11 | 16274664a23a97 |
12 | 60a012b1b94b7 |
13 | 24271b9444a81 |
14 | d5135a0175b5 |
15 | 63ca51d422a7 |
hex | 3137ef83368b |
54116311316107 has 4 divisors (see below), whose sum is σ = 54271372380400. Its totient is φ = 53961250251816.
The previous prime is 54116311316099. The next prime is 54116311316113. The reversal of 54116311316107 is 70161311361145.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54116311316107 - 23 = 54116311316099 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 54116311316107.
It is not an unprimeable number, because it can be changed into a prime (54116311386107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77530531623 + ... + 77530532320.
It is an arithmetic number, because the mean of its divisors is an integer number (13567843095100).
Almost surely, 254116311316107 is an apocalyptic number.
54116311316107 is a deficient number, since it is larger than the sum of its proper divisors (155061064293).
54116311316107 is a wasteful number, since it uses less digits than its factorization.
54116311316107 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155061064292.
The product of its (nonzero) digits is 45360, while the sum is 40.
The spelling of 54116311316107 in words is "fifty-four trillion, one hundred sixteen billion, three hundred eleven million, three hundred sixteen thousand, one hundred seven".
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