Base | Representation |
---|---|
bin | 11000100111000110110001… |
… | …01110111001101001011011 |
3 | 21002121211202110201012002200 |
4 | 30103203120232321221123 |
5 | 24043201204332244003 |
6 | 311034253203101243 |
7 | 14254025414432202 |
oct | 1423433056715133 |
9 | 232554673635080 |
10 | 54120224103003 |
11 | 1627629265a773 |
12 | 60a0a41671823 |
13 | 2427690c7bba6 |
14 | d5160b948239 |
15 | 63cbd05db6a3 |
hex | 3138d8bb9a5b |
54120224103003 has 12 divisors (see below), whose sum is σ = 78173814855240. Its totient is φ = 36080076563136.
The previous prime is 54120224102999. The next prime is 54120224103067. The reversal of 54120224103003 is 30030142202145.
54120224103003 is a `hidden beast` number, since 5 + 4 + 120 + 224 + 10 + 300 + 3 = 666.
It is not a de Polignac number, because 54120224103003 - 22 = 54120224102999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (54120224101003) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1154673 + ... + 10467746.
It is an arithmetic number, because the mean of its divisors is an integer number (6514484571270).
Almost surely, 254120224103003 is an apocalyptic number.
54120224103003 is a deficient number, since it is larger than the sum of its proper divisors (24053590752237).
54120224103003 is a wasteful number, since it uses less digits than its factorization.
54120224103003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12139818 (or 12139815 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 54120224103003 its reverse (30030142202145), we get a palindrome (84150366305148).
The spelling of 54120224103003 in words is "fifty-four trillion, one hundred twenty billion, two hundred twenty-four million, one hundred three thousand, three".
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