Base | Representation |
---|---|
bin | 100111011000011010010… |
… | …0010000100101110010001 |
3 | 201011102201020011122010200 |
4 | 1032300310202010232101 |
5 | 1202134340233443213 |
6 | 15302253035245413 |
7 | 1066020535045266 |
oct | 116606442045621 |
9 | 21142636148120 |
10 | 5412540140433 |
11 | 17a7499893a88 |
12 | 734ba08a9869 |
13 | 30352873493a |
14 | 149d7b1ab26d |
15 | 95bd4ed2273 |
hex | 4ec34884b91 |
5412540140433 has 12 divisors (see below), whose sum is σ = 8229593196240. Its totient is φ = 3418446404376.
The previous prime is 5412540140417. The next prime is 5412540140443. The reversal of 5412540140433 is 3340410452145.
5412540140433 is a `hidden beast` number, since 5 + 41 + 2 + 5 + 40 + 140 + 433 = 666.
It is not a de Polignac number, because 5412540140433 - 24 = 5412540140417 is a prime.
It is a super-2 number, since 2×54125401404332 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5412540140443) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15826140591 + ... + 15826140932.
It is an arithmetic number, because the mean of its divisors is an integer number (685799433020).
Almost surely, 25412540140433 is an apocalyptic number.
It is an amenable number.
5412540140433 is a deficient number, since it is larger than the sum of its proper divisors (2817053055807).
5412540140433 is a wasteful number, since it uses less digits than its factorization.
5412540140433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31652281548 (or 31652281545 counting only the distinct ones).
The product of its (nonzero) digits is 115200, while the sum is 36.
Adding to 5412540140433 its reverse (3340410452145), we get a palindrome (8752950592578).
The spelling of 5412540140433 in words is "five trillion, four hundred twelve billion, five hundred forty million, one hundred forty thousand, four hundred thirty-three".
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