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5413131103241 = 8365218447027
BaseRepresentation
bin100111011000101011111…
…0000011010110000001001
3201011111020102011122201002
41032301113300122300021
51202142043030300431
615302431425504345
71066041302125031
oct116612760326011
921144212148632
105413131103241
1117a777242a0a4
127351267a20b5
133035c0cb7c84
14149dd58808c1
1595c1bd173cb
hex4ec57c1ac09

5413131103241 has 4 divisors (see below), whose sum is σ = 5478349550352. Its totient is φ = 5347912656132.

The previous prime is 5413131103217. The next prime is 5413131103243. The reversal of 5413131103241 is 1423011313145.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-5413131103241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5413131103243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32609223431 + ... + 32609223596.

It is an arithmetic number, because the mean of its divisors is an integer number (1369587387588).

Almost surely, 25413131103241 is an apocalyptic number.

It is an amenable number.

5413131103241 is a deficient number, since it is larger than the sum of its proper divisors (65218447111).

5413131103241 is an equidigital number, since it uses as much as digits as its factorization.

5413131103241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65218447110.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 5413131103241 its reverse (1423011313145), we get a palindrome (6836142416386).

The spelling of 5413131103241 in words is "five trillion, four hundred thirteen billion, one hundred thirty-one million, one hundred three thousand, two hundred forty-one".

Divisors: 1 83 65218447027 5413131103241