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54134113 = 114921283
BaseRepresentation
bin1100111010000…
…0010101100001
310202212022001011
43032200111201
5102324242423
65212140521
71225063255
oct316402541
9122768034
1054134113
1128614840
1216167741
13b2a5027
147292265
154b44b0d
hex33a0561

54134113 has 4 divisors (see below), whose sum is σ = 59055408. Its totient is φ = 49212820.

The previous prime is 54134107. The next prime is 54134117. The reversal of 54134113 is 31143145.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54134113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54134117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2460631 + ... + 2460652.

It is an arithmetic number, because the mean of its divisors is an integer number (14763852).

Almost surely, 254134113 is an apocalyptic number.

It is an amenable number.

54134113 is a deficient number, since it is larger than the sum of its proper divisors (4921295).

54134113 is a wasteful number, since it uses less digits than its factorization.

54134113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4921294.

The product of its digits is 720, while the sum is 22.

The square root of 54134113 is about 7357.5888034056. The cubic root of 54134113 is about 378.2889670051.

Adding to 54134113 its reverse (31143145), we get a palindrome (85277258).

The spelling of 54134113 in words is "fifty-four million, one hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 11 4921283 54134113