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5413651433 = 17593077687
BaseRepresentation
bin1010000101010110…
…11100001111101001
3111222021201222122122
411002223130033221
542041343321213
62253105201025
7251104164221
oct50253341751
914867658578
105413651433
1123289574a3
121071030175
1368376ca58
14394dbb081
1521a414d08
hex142adc3e9

5413651433 has 4 divisors (see below), whose sum is σ = 5416730880. Its totient is φ = 5410571988.

The previous prime is 5413651429. The next prime is 5413651483. The reversal of 5413651433 is 3341563145.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5413651433 - 22 = 5413651429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5413651393 and 5413651402.

It is not an unprimeable number, because it can be changed into a prime (5413651403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1537085 + ... + 1540602.

It is an arithmetic number, because the mean of its divisors is an integer number (1354182720).

Almost surely, 25413651433 is an apocalyptic number.

It is an amenable number.

5413651433 is a deficient number, since it is larger than the sum of its proper divisors (3079447).

5413651433 is a wasteful number, since it uses less digits than its factorization.

5413651433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3079446.

The product of its digits is 64800, while the sum is 35.

The square root of 5413651433 is about 73577.5198888900. The cubic root of 5413651433 is about 1755.8878074492.

The spelling of 5413651433 in words is "five billion, four hundred thirteen million, six hundred fifty-one thousand, four hundred thirty-three".

Divisors: 1 1759 3077687 5413651433