5414231212433 has 4 divisors (see below), whose sum is σ = 5560561785780. Its totient is φ = 5267900639088.

The previous prime is 5414231212381. The next prime is 5414231212457. The reversal of 5414231212433 is 3342121324145.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3671638487104 + 1742592725329 = 1916152^2 + 1320073^2 .

It is a cyclic number.

It is not a de Polignac number, because 5414231212433 - 2¹⁰ = 5414231211409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5414231212393 and 5414231212402.

It is not an unprimeable number, because it can be changed into a prime (5414231214433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73165286618 + ... + 73165286691.

It is an arithmetic number, because the mean of its divisors is an integer number (1390140446445).

Almost surely, 2^{5414231212433} is an apocalyptic number.

It is an amenable number.

5414231212433 is a deficient number, since it is larger than the sum of its proper divisors (146330573347).

5414231212433 is a wasteful number, since it uses less digits than its factorization.

5414231212433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146330573346.

The product of its digits is 69120, while the sum is 35.

Adding to 5414231212433 its reverse (3342121324145), we get a palindrome (8756352536578).

The spelling of 5414231212433 in words is "five trillion, four hundred fourteen billion, two hundred thirty-one million, two hundred twelve thousand, four hundred thirty-three".