Base | Representation |
---|---|
bin | 11000100111110001010010… |
… | …11101001001111011000011 |
3 | 21002201000200110202121112010 |
4 | 30103320221131021323003 |
5 | 24044034433112221201 |
6 | 311052550354504003 |
7 | 14255464222055664 |
oct | 1423705135117303 |
9 | 232630613677463 |
10 | 54143053242051 |
11 | 16284a38059834 |
12 | 60a5352b95003 |
13 | 242988b816ba7 |
14 | d5277587b36b |
15 | 63d5b98eabd6 |
hex | 313e29749ec3 |
54143053242051 has 8 divisors (see below), whose sum is σ = 72623017522944. Its totient is φ = 35879228894600.
The previous prime is 54143053242037. The next prime is 54143053242101. The reversal of 54143053242051 is 15024235034145.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54143053242051 - 26 = 54143053241987 is a prime.
It is not an unprimeable number, because it can be changed into a prime (54143053242251) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 54034982775 + ... + 54034983776.
It is an arithmetic number, because the mean of its divisors is an integer number (9077877190368).
Almost surely, 254143053242051 is an apocalyptic number.
54143053242051 is a deficient number, since it is larger than the sum of its proper divisors (18479964280893).
54143053242051 is a wasteful number, since it uses less digits than its factorization.
54143053242051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108069966721.
The product of its (nonzero) digits is 288000, while the sum is 39.
Adding to 54143053242051 its reverse (15024235034145), we get a palindrome (69167288276196).
The spelling of 54143053242051 in words is "fifty-four trillion, one hundred forty-three billion, fifty-three million, two hundred forty-two thousand, fifty-one".
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