Base | Representation |
---|---|
bin | 100111011001111010001… |
… | …1110001000110100111001 |
3 | 201011202000122112102110011 |
4 | 1032303310132020310321 |
5 | 1202212434121143022 |
6 | 15303544351221521 |
7 | 1066163406202156 |
oct | 116636436106471 |
9 | 21152018472404 |
10 | 5415760334137 |
11 | 17a88a157a19a |
12 | 73573b2178a1 |
13 | 30391c923aba |
14 | 14a1a4b3122d |
15 | 95d22a6d977 |
hex | 4ecf4788d39 |
5415760334137 has 4 divisors (see below), whose sum is σ = 5433174354816. Its totient is φ = 5398346313460.
The previous prime is 5415760334123. The next prime is 5415760334143. The reversal of 5415760334137 is 7314330675145.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5415760334137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5415760334177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8707009873 + ... + 8707010494.
It is an arithmetic number, because the mean of its divisors is an integer number (1358293588704).
Almost surely, 25415760334137 is an apocalyptic number.
It is an amenable number.
5415760334137 is a deficient number, since it is larger than the sum of its proper divisors (17414020679).
5415760334137 is a wasteful number, since it uses less digits than its factorization.
5415760334137 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17414020678.
The product of its (nonzero) digits is 3175200, while the sum is 49.
The spelling of 5415760334137 in words is "five trillion, four hundred fifteen billion, seven hundred sixty million, three hundred thirty-four thousand, one hundred thirty-seven".
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