Base | Representation |
---|---|
bin | 100111011010000101111… |
… | …0101000100100111001001 |
3 | 201011210000221221101202010 |
4 | 1032310023311010213021 |
5 | 1202214234432102103 |
6 | 15304051310530133 |
7 | 1066206205166631 |
oct | 116641365044711 |
9 | 21153027841663 |
10 | 5416152222153 |
11 | 17a8a82804492 |
12 | 73582a506949 |
13 | 303982b84cba |
14 | 14a200bc36c1 |
15 | 95d4717d903 |
hex | 4ed0bd449c9 |
5416152222153 has 4 divisors (see below), whose sum is σ = 7221536296208. Its totient is φ = 3610768148100.
The previous prime is 5416152222121. The next prime is 5416152222179. The reversal of 5416152222153 is 3512222516145.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 5416152222153 - 25 = 5416152222121 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5416152222053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 902692037023 + ... + 902692037028.
It is an arithmetic number, because the mean of its divisors is an integer number (1805384074052).
Almost surely, 25416152222153 is an apocalyptic number.
It is an amenable number.
5416152222153 is a deficient number, since it is larger than the sum of its proper divisors (1805384074055).
5416152222153 is a wasteful number, since it uses less digits than its factorization.
5416152222153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1805384074054.
The product of its digits is 144000, while the sum is 39.
Adding to 5416152222153 its reverse (3512222516145), we get a palindrome (8928374738298).
The spelling of 5416152222153 in words is "five trillion, four hundred sixteen billion, one hundred fifty-two million, two hundred twenty-two thousand, one hundred fifty-three".
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