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542044433 = 7293264283
BaseRepresentation
bin100000010011101…
…111000100010001
31101202221201011202
4200103233010101
52102230410213
6125441520545
716301205320
oct4023570421
91352851152
10542044433
11258a74007
12131643155
13883b6368
1451dbc0b7
15328c0b58
hex204ef111

542044433 has 8 divisors (see below), whose sum is σ = 621595968. Its totient is φ = 463022064.

The previous prime is 542044421. The next prime is 542044453. The reversal of 542044433 is 334440245.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 542044433 - 24 = 542044417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 542044396 and 542044405.

It is not an unprimeable number, because it can be changed into a prime (542044453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130091 + ... + 134192.

It is an arithmetic number, because the mean of its divisors is an integer number (77699496).

Almost surely, 2542044433 is an apocalyptic number.

It is an amenable number.

542044433 is a deficient number, since it is larger than the sum of its proper divisors (79551535).

542044433 is a wasteful number, since it uses less digits than its factorization.

542044433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 264583.

The product of its (nonzero) digits is 23040, while the sum is 29.

The square root of 542044433 is about 23281.8477144749. The cubic root of 542044433 is about 815.3516657690.

Adding to 542044433 its reverse (334440245), we get a palindrome (876484678).

The spelling of 542044433 in words is "five hundred forty-two million, forty-four thousand, four hundred thirty-three".

Divisors: 1 7 293 2051 264283 1849981 77434919 542044433