Base | Representation |
---|---|
bin | 1111110001110000111… |
… | …01011100000110001011 |
3 | 1220211021210110220022211 |
4 | 13320320131130012023 |
5 | 32340221424330101 |
6 | 1053013205325551 |
7 | 54111032331634 |
oct | 7707035340613 |
9 | 1824253426284 |
10 | 542113120651 |
11 | 1999aa7a6343 |
12 | 890947068b7 |
13 | 3c175c3328b |
14 | 1c34a2d488b |
15 | e17cdc4c51 |
hex | 7e3875c18b |
542113120651 has 8 divisors (see below), whose sum is σ = 565888291200. Its totient is φ = 518730928320.
The previous prime is 542113120621. The next prime is 542113120693. The reversal of 542113120651 is 156021311245.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-542113120651 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (542113120621) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 98241736 + ... + 98247253.
It is an arithmetic number, because the mean of its divisors is an integer number (70736036400).
Almost surely, 2542113120651 is an apocalyptic number.
542113120651 is a deficient number, since it is larger than the sum of its proper divisors (23775170549).
542113120651 is a wasteful number, since it uses less digits than its factorization.
542113120651 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 196489109.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 542113120651 its reverse (156021311245), we get a palindrome (698134431896).
The spelling of 542113120651 in words is "five hundred forty-two billion, one hundred thirteen million, one hundred twenty thousand, six hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •