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542191213441 = 4312609097987
BaseRepresentation
bin1111110001111010001…
…11010101101110000001
31220211111020102102111101
413320331013111232001
532340401422312231
61053025035214401
754113001162463
oct7707507255601
91824436372441
10542191213441
11199a3a894639
12890b68a7401
133c189176527
141c356822133
15e184b9d661
hex7e3d1d5b81

542191213441 has 4 divisors (see below), whose sum is σ = 554800311472. Its totient is φ = 529582115412.

The previous prime is 542191213363. The next prime is 542191213451. The reversal of 542191213441 is 144312191245.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 144312191245 = 528862438249.

It is a cyclic number.

It is not a de Polignac number, because 542191213441 - 215 = 542191180673 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 542191213441.

It is not an unprimeable number, because it can be changed into a prime (542191213451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6304548951 + ... + 6304549036.

It is an arithmetic number, because the mean of its divisors is an integer number (138700077868).

Almost surely, 2542191213441 is an apocalyptic number.

It is an amenable number.

542191213441 is a deficient number, since it is larger than the sum of its proper divisors (12609098031).

542191213441 is a wasteful number, since it uses less digits than its factorization.

542191213441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12609098030.

The product of its digits is 34560, while the sum is 37.

The spelling of 542191213441 in words is "five hundred forty-two billion, one hundred ninety-one million, two hundred thirteen thousand, four hundred forty-one".

Divisors: 1 43 12609097987 542191213441