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54223647007345 = 510844729401469
BaseRepresentation
bin11000101010000111011010…
…01101111110001001110001
321002222201201012011002101021
430111003231031332021301
524101400012113213340
6311153555522535441
714264346343551514
oct1425035515761161
9232881635132337
1054223647007345
1116306135145532
1260b8aa5807581
1324343639737ca
14d5661d418d7b
156407350a4e4a
hex3150ed37e271

54223647007345 has 4 divisors (see below), whose sum is σ = 65068376408820. Its totient is φ = 43378917605872.

The previous prime is 54223647007307. The next prime is 54223647007393. The reversal of 54223647007345 is 54370074632245.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8977669868176 + 45245977139169 = 2996276^2 + 6726513^2 .

It is a cyclic number.

It is not a de Polignac number, because 54223647007345 - 213 = 54223646999153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54223647007292 and 54223647007301.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5422364700730 + ... + 5422364700739.

It is an arithmetic number, because the mean of its divisors is an integer number (16267094102205).

Almost surely, 254223647007345 is an apocalyptic number.

It is an amenable number.

54223647007345 is a deficient number, since it is larger than the sum of its proper divisors (10844729401475).

54223647007345 is a wasteful number, since it uses less digits than its factorization.

54223647007345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10844729401474.

The product of its (nonzero) digits is 16934400, while the sum is 52.

The spelling of 54223647007345 in words is "fifty-four trillion, two hundred twenty-three billion, six hundred forty-seven million, seven thousand, three hundred forty-five".

Divisors: 1 5 10844729401469 54223647007345