Base | Representation |
---|---|
bin | 100111011101011110010… |
… | …1100001011011010011001 |
3 | 201012110210002001112112212 |
4 | 1032322330230023122121 |
5 | 1202324123043101431 |
6 | 15311252053044505 |
7 | 1066554156664451 |
oct | 116727454133231 |
9 | 21173702045485 |
10 | 5423414425241 |
11 | 180106a06711a |
12 | 737116626735 |
13 | 30456c5b3ba7 |
14 | 14a6cd4b4d61 |
15 | 9611e9dc72b |
hex | 4eebcb0b699 |
5423414425241 has 4 divisors (see below), whose sum is σ = 5424692632272. Its totient is φ = 5422136218212.
The previous prime is 5423414425217. The next prime is 5423414425267. The reversal of 5423414425241 is 1425244143245.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5423414425241 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5423414425271) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 639097151 + ... + 639105636.
It is an arithmetic number, because the mean of its divisors is an integer number (1356173158068).
Almost surely, 25423414425241 is an apocalyptic number.
It is an amenable number.
5423414425241 is a deficient number, since it is larger than the sum of its proper divisors (1278207031).
5423414425241 is a wasteful number, since it uses less digits than its factorization.
5423414425241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1278207030.
The product of its digits is 614400, while the sum is 41.
Adding to 5423414425241 its reverse (1425244143245), we get a palindrome (6848658568486).
The spelling of 5423414425241 in words is "five trillion, four hundred twenty-three billion, four hundred fourteen million, four hundred twenty-five thousand, two hundred forty-one".
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