Base | Representation |
---|---|
bin | 100111011101101101110… |
… | …1001001111101011001011 |
3 | 201012112010021020222010211 |
4 | 1032323123221033223023 |
5 | 1202331204014444323 |
6 | 15311415404021551 |
7 | 1066603064115631 |
oct | 116733351175313 |
9 | 21175107228124 |
10 | 5423933749963 |
11 | 1801306222503 |
12 | 7372405318b7 |
13 | 304623073c21 |
14 | 14a73c45b351 |
15 | 961503c170d |
hex | 4eedba4facb |
5423933749963 has 16 divisors (see below), whose sum is σ = 5484686904000. Its totient is φ = 5363519936512.
The previous prime is 5423933749933. The next prime is 5423933749987. The reversal of 5423933749963 is 3699473393245.
5423933749963 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5423933749963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5423933749933) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45631653 + ... + 45750361.
It is an arithmetic number, because the mean of its divisors is an integer number (342792931500).
Almost surely, 25423933749963 is an apocalyptic number.
5423933749963 is a deficient number, since it is larger than the sum of its proper divisors (60753154037).
5423933749963 is a wasteful number, since it uses less digits than its factorization.
5423933749963 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 120134.
The product of its digits is 396809280, while the sum is 67.
The spelling of 5423933749963 in words is "five trillion, four hundred twenty-three billion, nine hundred thirty-three million, seven hundred forty-nine thousand, nine hundred sixty-three".
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