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5431132641731 = 27898119467751
BaseRepresentation
bin100111100001000100010…
…1110110101100111000011
3201020012200222020120010212
41033002020232311213003
51202440424424013411
615315010005144335
71100246346515366
oct117021056654703
921205628216125
105431132641731
11180436a872435
1273870b3bb0ab
133051cc6368b4
1414ac2258c0dd
15964223c668b
hex4f088bb59c3

5431132641731 has 4 divisors (see below), whose sum is σ = 5431152388464. Its totient is φ = 5431112895000.

The previous prime is 5431132641721. The next prime is 5431132641751. The reversal of 5431132641731 is 1371462311345.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5431132641731 - 26 = 5431132641667 is a prime.

It is a super-2 number, since 2×54311326417312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5431132641721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9454895 + ... + 10012856.

It is an arithmetic number, because the mean of its divisors is an integer number (1357788097116).

Almost surely, 25431132641731 is an apocalyptic number.

5431132641731 is a deficient number, since it is larger than the sum of its proper divisors (19746733).

5431132641731 is a wasteful number, since it uses less digits than its factorization.

5431132641731 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19746732.

The product of its digits is 181440, while the sum is 41.

The spelling of 5431132641731 in words is "five trillion, four hundred thirty-one billion, one hundred thirty-two million, six hundred forty-one thousand, seven hundred thirty-one".

Divisors: 1 278981 19467751 5431132641731