Base | Representation |
---|---|
bin | 100111100001000100010… |
… | …1110110101100111000011 |
3 | 201020012200222020120010212 |
4 | 1033002020232311213003 |
5 | 1202440424424013411 |
6 | 15315010005144335 |
7 | 1100246346515366 |
oct | 117021056654703 |
9 | 21205628216125 |
10 | 5431132641731 |
11 | 180436a872435 |
12 | 73870b3bb0ab |
13 | 3051cc6368b4 |
14 | 14ac2258c0dd |
15 | 964223c668b |
hex | 4f088bb59c3 |
5431132641731 has 4 divisors (see below), whose sum is σ = 5431152388464. Its totient is φ = 5431112895000.
The previous prime is 5431132641721. The next prime is 5431132641751. The reversal of 5431132641731 is 1371462311345.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5431132641731 - 26 = 5431132641667 is a prime.
It is a super-2 number, since 2×54311326417312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5431132641721) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9454895 + ... + 10012856.
It is an arithmetic number, because the mean of its divisors is an integer number (1357788097116).
Almost surely, 25431132641731 is an apocalyptic number.
5431132641731 is a deficient number, since it is larger than the sum of its proper divisors (19746733).
5431132641731 is a wasteful number, since it uses less digits than its factorization.
5431132641731 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19746732.
The product of its digits is 181440, while the sum is 41.
The spelling of 5431132641731 in words is "five trillion, four hundred thirty-one billion, one hundred thirty-two million, six hundred forty-one thousand, seven hundred thirty-one".
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