Base | Representation |
---|---|
bin | 100111100001100100100… |
… | …0100101111010111000001 |
3 | 201020022111012110222222011 |
4 | 1033003021010233113001 |
5 | 1203000132301000441 |
6 | 15315305050212521 |
7 | 1100315165131315 |
oct | 117031104572701 |
9 | 21208435428864 |
10 | 5432212125121 |
11 | 1804874144271 |
12 | 738970a24141 |
13 | 305342182c72 |
14 | 14acc5aa9b45 |
15 | 96487058581 |
hex | 4f0c912f5c1 |
5432212125121 has 16 divisors (see below), whose sum is σ = 5834656419840. Its totient is φ = 5039203553280.
The previous prime is 5432212125103. The next prime is 5432212125143. The reversal of 5432212125121 is 1215212122345.
It is a cyclic number.
It is not a de Polignac number, because 5432212125121 - 25 = 5432212125089 is a prime.
It is a super-2 number, since 2×54322121251212 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5432212125721) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2730145 + ... + 4279966.
It is an arithmetic number, because the mean of its divisors is an integer number (364666026240).
Almost surely, 25432212125121 is an apocalyptic number.
It is an amenable number.
5432212125121 is a deficient number, since it is larger than the sum of its proper divisors (402444294719).
5432212125121 is a wasteful number, since it uses less digits than its factorization.
5432212125121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7010784.
The product of its digits is 9600, while the sum is 31.
Adding to 5432212125121 its reverse (1215212122345), we get a palindrome (6647424247466).
The spelling of 5432212125121 in words is "five trillion, four hundred thirty-two billion, two hundred twelve million, one hundred twenty-five thousand, one hundred twenty-one".
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