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543224402041 = 604789833703
BaseRepresentation
bin1111110011110101011…
…00101001000001111001
31220221011020112211210211
413321322230221001321
532400010421331131
61053315344111121
754150415142236
oct7717254510171
91827136484724
10543224402041
1119a420016512
12893449054a1
133c2c2233b29
141c413b2c78d
15e1e57385b1
hex7e7ab29079

543224402041 has 4 divisors (see below), whose sum is σ = 543314241792. Its totient is φ = 543134562292.

The previous prime is 543224402029. The next prime is 543224402059. The reversal of 543224402041 is 140204422345.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 543224402041 - 215 = 543224369273 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 543224401994 and 543224402012.

It is not an unprimeable number, because it can be changed into a prime (543224402641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44910805 + ... + 44922898.

It is an arithmetic number, because the mean of its divisors is an integer number (135828560448).

Almost surely, 2543224402041 is an apocalyptic number.

It is an amenable number.

543224402041 is a deficient number, since it is larger than the sum of its proper divisors (89839751).

543224402041 is an equidigital number, since it uses as much as digits as its factorization.

543224402041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89839750.

The product of its (nonzero) digits is 30720, while the sum is 31.

Adding to 543224402041 its reverse (140204422345), we get a palindrome (683428824386).

The spelling of 543224402041 in words is "five hundred forty-three billion, two hundred twenty-four million, four hundred two thousand, forty-one".

Divisors: 1 6047 89833703 543224402041