Base | Representation |
---|---|
bin | 100111100001101000011… |
… | …1101011100111011011001 |
3 | 201020022211102102220100201 |
4 | 1033003100331130323121 |
5 | 1203000420133313340 |
6 | 15315330134102201 |
7 | 1100321362541545 |
oct | 117032075347331 |
9 | 21208742386321 |
10 | 5432344432345 |
11 | 18049318a1686 |
12 | 7389a91aa961 |
13 | 3053636c896c |
14 | 14acd94aaa25 |
15 | 9649399079a |
hex | 4f0d0f5ced9 |
5432344432345 has 16 divisors (see below), whose sum is σ = 6743790354960. Its totient is φ = 4195899316224.
The previous prime is 5432344432331. The next prime is 5432344432379.
5432344432345 is nontrivially palindromic in base 10.
It can be written as a sum of positive squares in 8 ways, for example, as 1079930404809 + 4352414027536 = 1039197^2 + 2086244^2 .
It is a cyclic number.
It is not a de Polignac number, because 5432344432345 - 27 = 5432344432217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5432344432295 and 5432344432304.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4810609 + ... + 5831521.
It is an arithmetic number, because the mean of its divisors is an integer number (421486897185).
Almost surely, 25432344432345 is an apocalyptic number.
It is an amenable number.
5432344432345 is a deficient number, since it is larger than the sum of its proper divisors (1311445922615).
5432344432345 is a wasteful number, since it uses less digits than its factorization.
5432344432345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1057644.
The product of its digits is 8294400, while the sum is 46.
The spelling of 5432344432345 in words is "five trillion, four hundred thirty-two billion, three hundred forty-four million, four hundred thirty-two thousand, three hundred forty-five".
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