Base | Representation |
---|---|
bin | 100111100001110100000… |
… | …0010000000111010111001 |
3 | 201020100211101210012021112 |
4 | 1033003220002000322321 |
5 | 1203002213231114223 |
6 | 15315432402250105 |
7 | 1100334102600341 |
oct | 117035002007271 |
9 | 21210741705245 |
10 | 5432731504313 |
11 | 1805010337573 |
12 | 738a96956935 |
13 | 3053c5961a29 |
14 | 14ad34a67d21 |
15 | 964b794d778 |
hex | 4f0e8080eb9 |
5432731504313 has 4 divisors (see below), whose sum is σ = 5439055988880. Its totient is φ = 5426407019748.
The previous prime is 5432731504297. The next prime is 5432731504367. The reversal of 5432731504313 is 3134051372345.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5432731504313 - 24 = 5432731504297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5438731504313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3162240995 + ... + 3162242712.
It is an arithmetic number, because the mean of its divisors is an integer number (1359763997220).
Almost surely, 25432731504313 is an apocalyptic number.
It is an amenable number.
5432731504313 is a deficient number, since it is larger than the sum of its proper divisors (6324484567).
5432731504313 is an equidigital number, since it uses as much as digits as its factorization.
5432731504313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6324484566.
The product of its (nonzero) digits is 453600, while the sum is 41.
Adding to 5432731504313 its reverse (3134051372345), we get a palindrome (8566782876658).
The spelling of 5432731504313 in words is "five trillion, four hundred thirty-two billion, seven hundred thirty-one million, five hundred four thousand, three hundred thirteen".
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