Base | Representation |
---|---|
bin | 110010100110100010… |
… | …100000011010001001 |
3 | 12012020121101110201000 |
4 | 302212202200122021 |
5 | 1342233404433144 |
6 | 40543251045213 |
7 | 3632303404140 |
oct | 624642403211 |
9 | 165217343630 |
10 | 54333671049 |
11 | 21051a39279 |
12 | a6442a0809 |
13 | 517b84b118 |
14 | 28b6100757 |
15 | 163007a769 |
hex | ca68a0689 |
54333671049 has 128 divisors (see below), whose sum is σ = 100208102400. Its totient is φ = 28386754560.
The previous prime is 54333671047. The next prime is 54333671053. The reversal of 54333671049 is 94017633345.
54333671049 is a `hidden beast` number, since 543 + 3 + 3 + 67 + 1 + 0 + 49 = 666.
It is not a de Polignac number, because 54333671049 - 21 = 54333671047 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 54333670995 and 54333671013.
It is not an unprimeable number, because it can be changed into a prime (54333671047) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 36489297 + ... + 36490785.
It is an arithmetic number, because the mean of its divisors is an integer number (782875800).
Almost surely, 254333671049 is an apocalyptic number.
It is an amenable number.
54333671049 is a deficient number, since it is larger than the sum of its proper divisors (45874431351).
54333671049 is a wasteful number, since it uses less digits than its factorization.
54333671049 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1840 (or 1834 counting only the distinct ones).
The product of its (nonzero) digits is 816480, while the sum is 45.
The spelling of 54333671049 in words is "fifty-four billion, three hundred thirty-three million, six hundred seventy-one thousand, forty-nine".
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