5433436343345 has 4 divisors (see below), whose sum is σ = 6520123612020. Its totient is φ = 4346749074672.

The previous prime is 5433436343341. The next prime is 5433436343381.

5433436343345 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3610501617424 + 1822934725921 = 1900132^2 + 1350161^2 .

It is a cyclic number.

It is not a de Polignac number, because 5433436343345 - 2² = 5433436343341 is a prime.

It is a super-3 number, since 3×5433436343345³ (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5433436343293 and 5433436343302.

It is not an unprimeable number, because it can be changed into a prime (5433436343341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 543343634330 + ... + 543343634339.

It is an arithmetic number, because the mean of its divisors is an integer number (1630030903005).

Almost surely, 2^{5433436343345} is an apocalyptic number.

It is an amenable number.

5433436343345 is a deficient number, since it is larger than the sum of its proper divisors (1086687268675).

5433436343345 is a wasteful number, since it uses less digits than its factorization.

5433436343345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1086687268674.

The product of its digits is 27993600, while the sum is 50.

The spelling of 5433436343345 in words is "five trillion, four hundred thirty-three billion, four hundred thirty-six million, three hundred forty-three thousand, three hundred forty-five".