Base | Representation |
---|---|
bin | 11000101101010111110101… |
… | …10101001110111110000001 |
3 | 21010101102112112010101111211 |
4 | 30112223322311032332001 |
5 | 24110213143401201340 |
6 | 311321223215410121 |
7 | 14305420306161166 |
oct | 1426537265167601 |
9 | 233342475111454 |
10 | 54335544553345 |
11 | 16349636414a80 |
12 | 6116713b23941 |
13 | 2441a873252a3 |
14 | d5bbd662806d |
15 | 6435d3a735ea |
hex | 316afad4ef81 |
54335544553345 has 16 divisors (see below), whose sum is σ = 71137876995648. Its totient is φ = 39512476575040.
The previous prime is 54335544553331. The next prime is 54335544553369.
54335544553345 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 54335544553345 - 239 = 53785788739457 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 54335544553345.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53026654 + ... + 54041623.
It is an arithmetic number, because the mean of its divisors is an integer number (4446117312228).
Almost surely, 254335544553345 is an apocalyptic number.
54335544553345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54335544553345 is a deficient number, since it is larger than the sum of its proper divisors (16802332442303).
54335544553345 is a wasteful number, since it uses less digits than its factorization.
54335544553345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107077520.
The product of its digits is 324000000, while the sum is 58.
It can be divided in two parts, 5433554 and 4553345, that added together give a palindrome (9986899).
The spelling of 54335544553345 in words is "fifty-four trillion, three hundred thirty-five billion, five hundred forty-four million, five hundred fifty-three thousand, three hundred forty-five".
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