Base | Representation |
---|---|
bin | 11000101101011000110000… |
… | …11011111010110001111011 |
3 | 21010101110211010201100122021 |
4 | 30112230120123322301323 |
5 | 24110220203023433111 |
6 | 311321344401135311 |
7 | 14305435516660321 |
oct | 1426543033726173 |
9 | 233343733640567 |
10 | 54336041233531 |
11 | 16349870814172 |
12 | 611683232a537 |
13 | 2441b361b72a5 |
14 | d5bc42597d11 |
15 | 643612482d71 |
hex | 316b186fac7b |
54336041233531 has 4 divisors (see below), whose sum is σ = 54336064203072. Its totient is φ = 54336018263992.
The previous prime is 54336041233501. The next prime is 54336041233633. The reversal of 54336041233531 is 13533214063345.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54336041233531 is a prime.
It is a super-2 number, since 2×543360412335312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54336041233501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7468171 + ... + 12823636.
It is an arithmetic number, because the mean of its divisors is an integer number (13584016050768).
Almost surely, 254336041233531 is an apocalyptic number.
54336041233531 is a deficient number, since it is larger than the sum of its proper divisors (22969541).
54336041233531 is a wasteful number, since it uses less digits than its factorization.
54336041233531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22969540.
The product of its (nonzero) digits is 1166400, while the sum is 43.
Adding to 54336041233531 its reverse (13533214063345), we get a palindrome (67869255296876).
The spelling of 54336041233531 in words is "fifty-four trillion, three hundred thirty-six billion, forty-one million, two hundred thirty-three thousand, five hundred thirty-one".
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