Base | Representation |
---|---|
bin | 100111100010100100011… |
… | …0001011000011111001001 |
3 | 201020112000111210122220221 |
4 | 1033011020301120133021 |
5 | 1203014024230044340 |
6 | 15320301421350041 |
7 | 1100422241246332 |
oct | 117051061303711 |
9 | 21215014718827 |
10 | 5434354534345 |
11 | 1805773509000 |
12 | 73926a408321 |
13 | 3055c3c9c129 |
14 | 14b04a435289 |
15 | 9656019b44a |
hex | 4f148c587c9 |
5434354534345 has 128 divisors (see below), whose sum is σ = 7794964606464. Its totient is φ = 3622085632000.
The previous prime is 5434354534333. The next prime is 5434354534361.
5434354534345 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5434354534345 - 25 = 5434354534313 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5434354534292 and 5434354534301.
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 3808236522 + ... + 3808237948.
It is an arithmetic number, because the mean of its divisors is an integer number (60898160988).
Almost surely, 25434354534345 is an apocalyptic number.
5434354534345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
5434354534345 is a deficient number, since it is larger than the sum of its proper divisors (2360610072119).
5434354534345 is a wasteful number, since it uses less digits than its factorization.
5434354534345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2344 (or 2322 counting only the distinct ones).
The product of its digits is 51840000, while the sum is 52.
The spelling of 5434354534345 in words is "five trillion, four hundred thirty-four billion, three hundred fifty-four million, five hundred thirty-four thousand, three hundred forty-five".
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