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54343644406147 = 672541613191281
BaseRepresentation
bin11000101101100110111011…
…00111101110000110000011
321010102012110000102112201001
430112303131213232012003
524110331240431444042
6311325043043352431
714306125111611325
oct1426633547560603
9233365400375631
1054343644406147
11163520125932a8
1261181b4682717
132442778459bb5
14d5c364285615
15643909be4bb7
hex316cdd9ee183

54343644406147 has 8 divisors (see below), whose sum is σ = 55154977866512. Its totient is φ = 53532317836800.

The previous prime is 54343644406111. The next prime is 54343644406151. The reversal of 54343644406147 is 74160444634345.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54343644406147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54343644206147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15433147 + ... + 18624427.

It is an arithmetic number, because the mean of its divisors is an integer number (6894372233314).

Almost surely, 254343644406147 is an apocalyptic number.

54343644406147 is a deficient number, since it is larger than the sum of its proper divisors (811333460365).

54343644406147 is a wasteful number, since it uses less digits than its factorization.

54343644406147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3445509.

The product of its (nonzero) digits is 46448640, while the sum is 55.

The spelling of 54343644406147 in words is "fifty-four trillion, three hundred forty-three billion, six hundred forty-four million, four hundred six thousand, one hundred forty-seven".

Divisors: 1 67 254161 3191281 17028787 213815827 811099170241 54343644406147