Base | Representation |
---|---|
bin | 110010100111100110… |
… | …001010010011111011 |
3 | 12012021211202111221022 |
4 | 302213212022103323 |
5 | 1342302430000311 |
6 | 40545123133055 |
7 | 3632610221405 |
oct | 624746122373 |
9 | 165254674838 |
10 | 54351406331 |
11 | 21060a52032 |
12 | a64a21418b |
13 | 518241a781 |
14 | 28b85d9b75 |
15 | 16318d05db |
hex | ca798a4fb |
54351406331 has 4 divisors (see below), whose sum is σ = 54458187600. Its totient is φ = 54244625064.
The previous prime is 54351406313. The next prime is 54351406339. The reversal of 54351406331 is 13360415345.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54351406331 - 214 = 54351389947 is a prime.
It is a super-2 number, since 2×543514063312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54351406291 and 54351406300.
It is not an unprimeable number, because it can be changed into a prime (54351406339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53389871 + ... + 53390888.
It is an arithmetic number, because the mean of its divisors is an integer number (13614546900).
Almost surely, 254351406331 is an apocalyptic number.
54351406331 is a deficient number, since it is larger than the sum of its proper divisors (106781269).
54351406331 is a wasteful number, since it uses less digits than its factorization.
54351406331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106781268.
The product of its (nonzero) digits is 64800, while the sum is 35.
The spelling of 54351406331 in words is "fifty-four billion, three hundred fifty-one million, four hundred six thousand, three hundred thirty-one".
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