Base | Representation |
---|---|
bin | 100111100101010010101… |
… | …1001001100110101000001 |
3 | 201021002010010120000221201 |
4 | 1033022211121030311001 |
5 | 1203113014040143041 |
6 | 15323110040021201 |
7 | 1101020212202560 |
oct | 117124531146501 |
9 | 21232103500851 |
10 | 5440203443521 |
11 | 18081a5022040 |
12 | 73a421161801 |
13 | 306016976632 |
14 | 14b443153bd7 |
15 | 967a38db631 |
hex | 4f2a564cd41 |
5440203443521 has 16 divisors (see below), whose sum is σ = 6797901938688. Its totient is φ = 4229550421200.
The previous prime is 5440203443509. The next prime is 5440203443533. The reversal of 5440203443521 is 1253443020445.
It is an interprime number because it is at equal distance from previous prime (5440203443509) and next prime (5440203443533).
It is a cyclic number.
It is not a de Polignac number, because 5440203443521 - 217 = 5440203312449 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5440203443581) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79708545 + ... + 79776766.
It is an arithmetic number, because the mean of its divisors is an integer number (424868871168).
Almost surely, 25440203443521 is an apocalyptic number.
It is an amenable number.
5440203443521 is a deficient number, since it is larger than the sum of its proper divisors (1357698495167).
5440203443521 is a wasteful number, since it uses less digits than its factorization.
5440203443521 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159485772.
The product of its (nonzero) digits is 230400, while the sum is 37.
Adding to 5440203443521 its reverse (1253443020445), we get a palindrome (6693646463966).
The spelling of 5440203443521 in words is "five trillion, four hundred forty billion, two hundred three million, four hundred forty-three thousand, five hundred twenty-one".
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