Base | Representation |
---|---|
bin | 110010101010100111… |
… | …010100011000001011 |
3 | 12012102101001001010120 |
4 | 302222213110120023 |
5 | 1342403410310410 |
6 | 40554132314323 |
7 | 3634063502364 |
oct | 625247243013 |
9 | 165371031116 |
10 | 54402041355 |
11 | 21087596962 |
12 | a6631729a3 |
13 | 518ca68c1c |
14 | 28c121ab6b |
15 | 1636083570 |
hex | caa9d460b |
54402041355 has 16 divisors (see below), whose sum is σ = 87054497280. Its totient is φ = 29010678368.
The previous prime is 54402041303. The next prime is 54402041357. The reversal of 54402041355 is 55314020445.
It is a cyclic number.
It is not a de Polignac number, because 54402041355 - 210 = 54402040331 is a prime.
It is a super-3 number, since 3×544020413553 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (54402041357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 111795 + ... + 348284.
It is an arithmetic number, because the mean of its divisors is an integer number (5440906080).
Almost surely, 254402041355 is an apocalyptic number.
54402041355 is a deficient number, since it is larger than the sum of its proper divisors (32652455925).
54402041355 is a wasteful number, since it uses less digits than its factorization.
54402041355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 467970.
The product of its (nonzero) digits is 48000, while the sum is 33.
The spelling of 54402041355 in words is "fifty-four billion, four hundred two million, forty-one thousand, three hundred fifty-five".
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