Search a number
-
+
544042454313 = 3181347484771
BaseRepresentation
bin1111110101010110111…
…01010000110100101001
31221000021020212012120010
413322223131100310221
532403144332014223
61053532445522133
754206610363261
oct7725335206451
91830236765503
10544042454313
1119a7aa867276
1289532873349
133c3c2867727
141c4906367a1
15e242479393
hex7eab750d29

544042454313 has 4 divisors (see below), whose sum is σ = 725389939088. Its totient is φ = 362694969540.

The previous prime is 544042454297. The next prime is 544042454327. The reversal of 544042454313 is 313454240445.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 544042454313 - 24 = 544042454297 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (544042454363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90673742383 + ... + 90673742388.

It is an arithmetic number, because the mean of its divisors is an integer number (181347484772).

Almost surely, 2544042454313 is an apocalyptic number.

It is an amenable number.

544042454313 is a deficient number, since it is larger than the sum of its proper divisors (181347484775).

544042454313 is a wasteful number, since it uses less digits than its factorization.

544042454313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 181347484774.

The product of its (nonzero) digits is 460800, while the sum is 39.

Adding to 544042454313 its reverse (313454240445), we get a palindrome (857496694758).

The spelling of 544042454313 in words is "five hundred forty-four billion, forty-two million, four hundred fifty-four thousand, three hundred thirteen".

Divisors: 1 3 181347484771 544042454313