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54411221334451 = 61891987234991
BaseRepresentation
bin11000101111100100110011…
…00001001111100110110011
321010122122212120100012002111
430113302121201033212303
524112433140130200301
6311420100415430151
714314036534203112
oct1427623141174663
9233578776305074
1054411221334451
111637873aa44783
126129313b25357
132448c5789b2c7
14d61735153c79
15645562723551
hex317c9984f9b3

54411221334451 has 4 divisors (see below), whose sum is σ = 55303208569504. Its totient is φ = 53519234099400.

The previous prime is 54411221334433. The next prime is 54411221334493. The reversal of 54411221334451 is 15443312211445.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54411221334451 - 245 = 19226849245619 is a prime.

It is a super-2 number, since 2×544112213344512 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54411221334751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 445993617435 + ... + 445993617556.

It is an arithmetic number, because the mean of its divisors is an integer number (13825802142376).

Almost surely, 254411221334451 is an apocalyptic number.

54411221334451 is a deficient number, since it is larger than the sum of its proper divisors (891987235053).

54411221334451 is an equidigital number, since it uses as much as digits as its factorization.

54411221334451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 891987235052.

The product of its digits is 230400, while the sum is 40.

Adding to 54411221334451 its reverse (15443312211445), we get a palindrome (69854533545896).

The spelling of 54411221334451 in words is "fifty-four trillion, four hundred eleven billion, two hundred twenty-one million, three hundred thirty-four thousand, four hundred fifty-one".

Divisors: 1 61 891987234991 54411221334451