Base | Representation |
---|---|
bin | 11000101111101001110010… |
… | …11000011110101101000011 |
3 | 21010122220210111002210202210 |
4 | 30113310321120132231003 |
5 | 24113004133232012210 |
6 | 311421222505313203 |
7 | 14314163152255431 |
oct | 1427647130365503 |
9 | 233586714083683 |
10 | 54413903391555 |
11 | 163798969959a4 |
12 | 6129942195803 |
13 | 2449294441a46 |
14 | d6190b435d51 |
15 | 64566ce11e20 |
hex | 317d3961eb43 |
54413903391555 has 16 divisors (see below), whose sum is σ = 87062370577920. Its totient is φ = 29020706758368.
The previous prime is 54413903391541. The next prime is 54413903391577. The reversal of 54413903391555 is 55519330931445.
It is not a de Polignac number, because 54413903391555 - 24 = 54413903391539 is a prime.
It is a super-3 number, since 3×544139033915553 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54413903391495 and 54413903391504.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10206886 + ... + 14594804.
It is an arithmetic number, because the mean of its divisors is an integer number (5441398161120).
Almost surely, 254413903391555 is an apocalyptic number.
54413903391555 is a deficient number, since it is larger than the sum of its proper divisors (32648467186365).
54413903391555 is a wasteful number, since it uses less digits than its factorization.
54413903391555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5214650.
The product of its (nonzero) digits is 21870000, while the sum is 57.
The spelling of 54413903391555 in words is "fifty-four trillion, four hundred thirteen billion, nine hundred three million, three hundred ninety-one thousand, five hundred fifty-five".
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