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544252211131 = 2054326493317
BaseRepresentation
bin1111110101101111111…
…01011010111110111011
31221000210212112221211011
413322313331122332323
532404112031224011
61054005341414351
754215035315216
oct7726775327673
91830725487734
10544252211131
1119a8a8203712
1289590b6a3b7
133c4271599a5
141c4b043877d
15e255aae621
hex7eb7f5afbb

544252211131 has 4 divisors (see below), whose sum is σ = 544278724992. Its totient is φ = 544225697272.

The previous prime is 544252211039. The next prime is 544252211159. The reversal of 544252211131 is 131112252445.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 544252211131 - 27 = 544252211003 is a prime.

It is a super-2 number, since 2×5442522111312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 544252211093 and 544252211102.

It is not an unprimeable number, because it can be changed into a prime (544252212131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13226116 + ... + 13267201.

It is an arithmetic number, because the mean of its divisors is an integer number (136069681248).

Almost surely, 2544252211131 is an apocalyptic number.

544252211131 is a deficient number, since it is larger than the sum of its proper divisors (26513861).

544252211131 is a wasteful number, since it uses less digits than its factorization.

544252211131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26513860.

The product of its digits is 9600, while the sum is 31.

Adding to 544252211131 its reverse (131112252445), we get a palindrome (675364463576).

The spelling of 544252211131 in words is "five hundred forty-four billion, two hundred fifty-two million, two hundred eleven thousand, one hundred thirty-one".

Divisors: 1 20543 26493317 544252211131