Base | Representation |
---|---|
bin | 110010101100011110… |
… | …101001110001010001 |
3 | 12012111112220101000020 |
4 | 302230132221301101 |
5 | 1342434412332423 |
6 | 41001211014053 |
7 | 3634623422640 |
oct | 625436516121 |
9 | 165445811006 |
10 | 54433324113 |
11 | 210a3213083 |
12 | a67173a329 |
13 | 519639ca2c |
14 | 28c5441357 |
15 | 1638bb24e3 |
hex | cac7a9c51 |
54433324113 has 8 divisors (see below), whose sum is σ = 82946017728. Its totient is φ = 31104756624.
The previous prime is 54433324093. The next prime is 54433324171. The reversal of 54433324113 is 31142333445.
54433324113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 54433324113 - 25 = 54433324081 is a prime.
It is not an unprimeable number, because it can be changed into a prime (54433324193) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1296031506 + ... + 1296031547.
It is an arithmetic number, because the mean of its divisors is an integer number (10368252216).
Almost surely, 254433324113 is an apocalyptic number.
It is an amenable number.
54433324113 is a deficient number, since it is larger than the sum of its proper divisors (28512693615).
54433324113 is a wasteful number, since it uses less digits than its factorization.
54433324113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2592063063.
The product of its digits is 51840, while the sum is 33.
Adding to 54433324113 its reverse (31142333445), we get a palindrome (85575657558).
It can be divided in two parts, 5443332 and 4113, that added together give a palindrome (5447445).
The spelling of 54433324113 in words is "fifty-four billion, four hundred thirty-three million, three hundred twenty-four thousand, one hundred thirteen".
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