Base | Representation |
---|---|
bin | 111101111001011010001111… |
… | …1001110011010111001110001 |
3 | 2122101202002220200221210110020 |
4 | 1323302310133032122321301 |
5 | 1032330300301101320340 |
6 | 5205541453103554053 |
7 | 222452235266434353 |
oct | 17362643716327161 |
9 | 2571662820853406 |
10 | 544452053151345 |
11 | 14852a901193949 |
12 | 51092556bbb929 |
13 | 1a4a47ba5cbb81 |
14 | 98638972db0d3 |
15 | 42e26a9c249d0 |
hex | 1ef2d1f39ae71 |
544452053151345 has 128 divisors (see below), whose sum is σ = 936526485307392. Its totient is φ = 269593414041600.
The previous prime is 544452053151343. The next prime is 544452053151421. The reversal of 544452053151345 is 543151350254445.
It is not a de Polignac number, because 544452053151345 - 21 = 544452053151343 is a prime.
It is a super-3 number, since 3×5444520531513453 (a number of 45 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (544452053151343) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 736664482 + ... + 737403188.
It is an arithmetic number, because the mean of its divisors is an integer number (7316613166464).
Almost surely, 2544452053151345 is an apocalyptic number.
It is an amenable number.
544452053151345 is a deficient number, since it is larger than the sum of its proper divisors (392074432156047).
544452053151345 is a wasteful number, since it uses less digits than its factorization.
544452053151345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 739431.
The product of its (nonzero) digits is 14400000, while the sum is 51.
The spelling of 544452053151345 in words is "five hundred forty-four trillion, four hundred fifty-two billion, fifty-three million, one hundred fifty-one thousand, three hundred forty-five".
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