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54476244913 = 311757298223
BaseRepresentation
bin110010101111000010…
…011000011110110001
312012121112122222021111
4302233002120132301
51343031404314123
641005342553321
73635654304316
oct625702303661
9165545588244
1054476244913
1121115469112
12a683b98841
1351a2249b5c
1428cb014d0d
15163c83e90d
hexcaf0987b1

54476244913 has 4 divisors (see below), whose sum is σ = 56233543168. Its totient is φ = 52718946660.

The previous prime is 54476244899. The next prime is 54476244929. The reversal of 54476244913 is 31944267445.

54476244913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54476244913 - 217 = 54476113841 is a prime.

It is a super-2 number, since 2×544762449132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54476244973) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 878649081 + ... + 878649142.

It is an arithmetic number, because the mean of its divisors is an integer number (14058385792).

Almost surely, 254476244913 is an apocalyptic number.

It is an amenable number.

54476244913 is a deficient number, since it is larger than the sum of its proper divisors (1757298255).

54476244913 is a wasteful number, since it uses less digits than its factorization.

54476244913 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1757298254.

The product of its digits is 2903040, while the sum is 49.

The spelling of 54476244913 in words is "fifty-four billion, four hundred seventy-six million, two hundred forty-four thousand, nine hundred thirteen".

Divisors: 1 31 1757298223 54476244913