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5450108113 = 10352913671
BaseRepresentation
bin1010001001101101…
…00000110011010001
3112001211100011211001
411010312200303101
542130211424423
62300450422001
7252026104012
oct50466406321
915054304731
105450108113
11234749798a
121081291901
1368b195858
14399b8b009
1521d716cad
hex144da0cd1

5450108113 has 4 divisors (see below), whose sum is σ = 5503021888. Its totient is φ = 5397194340.

The previous prime is 5450108101. The next prime is 5450108119. The reversal of 5450108113 is 3118010545.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5450108113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5450108119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26456733 + ... + 26456938.

It is an arithmetic number, because the mean of its divisors is an integer number (1375755472).

Almost surely, 25450108113 is an apocalyptic number.

It is an amenable number.

5450108113 is a deficient number, since it is larger than the sum of its proper divisors (52913775).

5450108113 is a wasteful number, since it uses less digits than its factorization.

5450108113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52913774.

The product of its (nonzero) digits is 2400, while the sum is 28.

The square root of 5450108113 is about 73824.8475311666. The cubic root of 5450108113 is about 1759.8205000520.

Adding to 5450108113 its reverse (3118010545), we get a palindrome (8568118658).

The spelling of 5450108113 in words is "five billion, four hundred fifty million, one hundred eight thousand, one hundred thirteen".

Divisors: 1 103 52913671 5450108113