Base | Representation |
---|---|
bin | 110010110000100001… |
… | …011011101010100011 |
3 | 12012200021112212121001 |
4 | 302300201123222203 |
5 | 1343104244133020 |
6 | 41012033012431 |
7 | 3636406141654 |
oct | 626041335243 |
9 | 165607485531 |
10 | 54501161635 |
11 | 21128537448 |
12 | a6903b4117 |
13 | 51a746218b |
14 | 28d045d52b |
15 | 163eb1250a |
hex | cb085baa3 |
54501161635 has 16 divisors (see below), whose sum is σ = 65935236096. Its totient is φ = 43245232128.
The previous prime is 54501161633. The next prime is 54501161641. The reversal of 54501161635 is 53616110545.
It is a cyclic number.
It is not a de Polignac number, because 54501161635 - 21 = 54501161633 is a prime.
It is a super-3 number, since 3×545011616353 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54501161594 and 54501161603.
It is not an unprimeable number, because it can be changed into a prime (54501161633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2667619 + ... + 2687971.
It is an arithmetic number, because the mean of its divisors is an integer number (4120952256).
Almost surely, 254501161635 is an apocalyptic number.
54501161635 is a deficient number, since it is larger than the sum of its proper divisors (11434074461).
54501161635 is a wasteful number, since it uses less digits than its factorization.
54501161635 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24702.
The product of its (nonzero) digits is 54000, while the sum is 37.
The spelling of 54501161635 in words is "fifty-four billion, five hundred one million, one hundred sixty-one thousand, six hundred thirty-five".
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